Solve the system of linear equations by elimination. 5x=4y+8 5x=4y+8 3y=3x−3

Solve the following system using elimination:
{5 x = 4 y + 8 | (equation 1)
{3 y = 3 x - 3 | (equation 2)

Express the system in standard form:
{5 x - 4 y = 8 | (equation 1)
{-(3 x) + 3 y = -3 | (equation 2)

Add 3/5 × (equation 1) to equation 2:
{5 x - 4 y = 8 | (equation 1)
{0 x+(3 y)/5 = 9/5 | (equation 2)

Multiply equation 2 by 5/3:
{5 x - 4 y = 8 | (equation 1)
{0 x+y = 3 | (equation 2)

Add 4 × (equation 2) to equation 1:
{5 x+0 y = 20 | (equation 1)
{0 x+y = 3 | (equation 2)

Divide equation 1 by 5:
{x+0 y = 4 | (equation 1)
{0 x+y = 3 | (equation 2)
Collect results:
  {x = 4
                {y = 3

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.