Camden is collecting bugs for science class the first day sister him he finds 35 bugs after day two he has 52 bugs on day three he has 69 bugs how many bugs will he have on the 15th day

Number of bugs on 1st day = 35

Number of bugs on 1st 2nd day = 52

Number of bugs on 3rd day = 69

35,52,69,

From the above sequence it is clear that the common difference 17 which is constant.

So the given sequence is in AP

Formula for nth term is

a(n)= a1 + (n-1) *d

n = number of terms = 15

d= common difference = 17

a1 = first term = 35

So a(15) = 35 + (15-1)*17

a(15) = 35 + 14(17)

a(15) = 35 + 238

a(15) = 273

So number of bugs on 15th day is 273

for b its (t) and c its (d)

step-by-step explanation: