Aparticle moves on a line away from its initial position so that after t hours it is s = 4t^2 + t miles from its initial position. find the average velocity of the particle over the interval [1, 4]. include units in your answer.

Average velocity is 21 miles/hr

Step-by-step explanation:

Given a particle moving away from its initial position

Position after t hours that is

                    s(t) = 4 + t

We have to find the average velocity of the particle over the interval [1,4]

Average velocity =

             Distance travelled =

                                             = s(4) - s(1)

                                             = 4 + 4 - 4 -1

                                             =  63 miles

                Time elapsed = 4 - 1 = 3

Average velocity =

                             = 21 miles/hr

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.

step-by-step explanation:

; fx