The sum of the square of a positive number and the square of 3 more than the number is 17 what is the number

The number is equal to 1.

In this exercise, you're required to write an algebraic expression and solve for the unknown variable or number.

Translating the word problem into an algebraic expression, we have;

Dividing all through by 2, we have;

Solving the quadratic equation by factorization, we have;

Since the number is a positive number, then p = 1

Therefore, the number is equal to 1.

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  1

Step-by-step explanation:

Let x represent the number. The given relation is ...

  x² +(x+3)² = 17

  2x² +6x +9 = 17 . . . . simplify

  x² +3x -4 = 0 . . . . . . subtract 17 and divide by 2

  (x +4)(x -1) = 0 . . . . . factor

The solutions make these factors zero: -4 and +1. The positive solution is 1.

The number is 1.

my acc plz

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!