Mathematics, 22.08.2019 05:40 kenisonpaigebosma

Find the exact value of tan 30 degrees w/o calculator

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$Look\ at\ the\ picture.\\\\tan30^o=\frac{\frac{a}{2}}{\frac{a\sqrt3}{2}}=\frac{a}{2}:\frac{a\sqrt3}{2}=\frac{a}{2}\cdot\frac{2}{a\sqrt3}=\frac{1}{\sqrt3}\cdot\frac{\sqrt3}{\sqrt3}=\frac{\sqrt3}{3}$
Find the exact value of tan 30 degrees w/o calculator

Find the exact value of tan 30 degrees w/o calculator

Answer from: LindaCat78

Here is a mantra that I learned in Geometry class in high school. We were
all very excited, as angles had been invented only a few years earlier:

In a 30-60 right triangle ...
the side opposite the 30 is half the hypotenuse
the side opposite the 60 is half the hypotenuse times the square root of three.

So the tangent of the 30 would be (opposite) / (adjacent) = (1/2h) / (1/2h√3) .

That's (1)/(√3) or (√3)/(3) .

Answer from: Quest

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w

Answer from: Quest

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly, giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

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