*a triangle has sides x, x+4 and 3x− 5. what is the possible range of x? answer like this: _

I hope this will help...

Given a triangle with sides C= x, A= x+4 and B= 3x− 5 the sum of the lengths of any sides of a triangle must be greater than the third side.

1. x + x+4 > 3x-5  2. x+4 + 3x-5 > x  3. x + 3x-5 > x+4  
1. x + x+4 > 3x-5  -> x < 92. x+4 + 3x-5 > x  -> x < 1/33. x + 3x-5 > x+4  -> x < 3

which implies that the possible range of x is  3 < x < 9

Y’all got to do it all over