Given the function g(x) = 6(4)x, section a is from x = 0 to x = 1 and section b is from x = 2 to x = 3. part a: find the average rate of change of each section. (4 points) part b: how many times greater is the average rate of change of section b than section a? explain why one rate of change is greater than the other. (6 points)

g(x) = 6(4)x, Section A is from x = 0 to x = 1.  Your "6(4)x" needs to be written as 

g(x) = 6(4)^x, where the " ^ " indicates exponentiation.

The average rate of change of g(x) from x= 0 to x=1 is:

              6(4)^1 - 6(4)^0         24 - 6
a.r.c. = = = 18 (answer)
                    1-0                         1

Now do the same thing for x = 1 to x = 2.

The answer is poppy pants69

The answer is a 5/20 because if u add all of the marbles there are 20 and there are 5 red marbles so 5/20 is the answer mark as brainliest