The   area of triangle formed by points of intersection of parabola y=a(x+5)(x−1) with the coordinate axes is 12. find a if it is known that parabola opens upward.

We know that the points at which the parabola intersects the x axis are

(-5,0) and (1,0)

So the extent between these two points would be the base of the triangle

lets find the length of the base using the distance formula

the base b=6

We will get the height of the triangle when we put x=0 in the equation

y=a(0+5)(0-1)

y=-5a

so height = -5a (we take +5a since it is the height)

We know that the area of the triangle =

× 6 × (5a) = 12

15a=12

a=

ion

step-by-step explanation:

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