Solve the equation 1/5(x-2)=1/10(x+6)

1/5(x-2)=1/10(x+6)
Distribute and multiply first
(1/5*x) -(1/5*2)=(1/10*x) +(1/10*6)
1/5x-2/5=1/10x+6/10

We do not have the same denominators on both sides. 5 goes into 10 two times so we will multiply everything on the left by 2 to get a common denominator.
2/10x-4/10=1/10x+6/10
Subtract 1/10x from both sides
1/10x-4/10=6/10
Add 4/10 to both sides
1/10x=10/10
1/10x= 1
Multiply both sides by 10/1 (the fraction inverse) to get rid of the fraction.

(10/1)(1/10x) =(1)(10/1)
x= 10

Check work:
1/5(x-2)=1/10(x+6)
Substitute your answer for x
1/5(10-2)=1/10(10+6)
1/5(8)=1/10(16)
8/5=16/10
Simplify 16/10 by dividing by 2
8/5=8/5

Hope this helps!! :)

The answer would be c