Find the distance of the line segment joining the two points: (5, 4) and (−2, 1)

Compute the Euclidean distance between the following points:
p_1 = (5, 4) and p_2 = (-2, 1)
The Euclidean distance between points (x_1, y_1) and (x_2, y_2) is:
sqrt((x_1 - x_2)^2 + (y_1 - y_2)^2)
Substitute (x_1, y_1) = (5, 4) and (x_2, y_2) = (-2, 1):
= sqrt((-(-2) + 5)^2 + (4 - 1)^2)
-(-2) = 2:
= sqrt((2 + 5)^2 + (4 - 1)^2)
5 + 2 = 7:
= sqrt(7^2 + (4 - 1)^2)
4 - 1 = 3:
= sqrt(7^2 + 3^2)
7^2 = 49:
= sqrt(49 + 3^2)
3^2 = 9:
= sqrt(49 + 9)
| 1 |
| 4 | 9
+ | | 9
| 5 | 8:
|
| = sqrt(58 )

Answer 20 centimeters15+8=2323-3=20so the answer is 20 centimeters