6x^2+x-1=0can someone explain in a simple

STEP 1 : Find two numbers which add to give you 1 (because of the +x in the middle) and multiply to give you - 6 (because - 1 * 6)

STEP 2 : Input both of these numbers in place of the + x
6x^2 - 2x + 3x - 1 = 0
This is because your 2 numbers are - 2 and 3

STEP 3 : Split the equation into a half and factorise them
This will give you : (6x-2) and (2x+1)

STEP 4 : Equal both of these brackets to 0 and make x the subject of both of the 2 formulaes
This will give you
6x - 2 = 0
6x = 2
x = 1/3
And
2x + 1 = 0
2x = - 1
x = - 1/2

I have attached my working out incase you don't understand