If polygon mast with coordinates m(-3,-1), a(-3,2),s (-1,3) and t (1,1) is reflected across x=-3, then which of the following coordinates represent the vertices of the polygon man's'? select all that apply

Let 'a' be the point and 'A' be the reflection of point 'a' through line x= -3

we know, (a+A)/2 (mid point of line aA) should lie on line x= -3

so by using this, we calculate vertices of reflected shape of MAST, we get

(-3,-1), (-3,2),(-5,3) and (-7,1)

Answer with explanation:

→The Polygon MAST has coordinates "M(-3,-1), A(-3,2),S (-1,3) T (1,1)".

Now, the polygon is reflected across , line ,x= -3.

Now, the Meaning of reflection is that ,the Shape and size of Image before and after Reflection does not change.

And when you , reflect the polygon which is a quadrilateral having vertices M, A, S, and T, the perpendicular distance from line , x=-3, from each of the vertices of the Quadrilateral,Called Pre-Image, will be same from each of the Vertices of the polygon after Reflection Called Image.

When , "polygon MAST is reflected across line", x=-3, the vertices of Image M'A'S'T' will be

M(-3,-1)→M'(-3,-1)

A(-3,2)→A'(-3,-2)

S(-1,3)→S'(-5,3)

T(1,1)→T'(-7,1)

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)