Terra writes the following proof for the theorem: if the diagonals of a quadrilateral bisect each other, the quadrilateral is a parallelogram: terra's proof 1. ao = oc because it is given that diagonals bisect each other. 2. bo = od because it is given that diagonals bisect each other. 3. for triangles aob and cod, angle 1 is equal to angle 2 as they are 4. therefore, the triangles aob and cod are congruent by sas postulate. 5. similarly, triangles aod and cob are congruent. 6. by cpctc, angle abd is equal to angle bdc and angle adb is equal to angle dbc. 7. as the alternate interior angles are congruent the opposite sides of quadrilateral abcd are parallel. 8. therefore, abcd is a parallelogram. which is the missing phrase in terra's proof?

36

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true