Drag each expression to show whether it is equivalent to 54x + 18, 18(3x – 1), or (6 • 9x) + (6 • 1).  a.54x + 6 b(9 • 6x) – (9 • 2) c.54x – 18 18(3x + 1) d(6 • 9x) + (6 • 3) e.3(18x+2)

54x + 18 -> (6 • 9x) + (6 • 3) and 18(3x + 1)

18(3x – 1) -> (9 • 6x) – (9 • 2) and 54x – 18

(6 • 9x) + (6 • 1) -> 3(18x+2) and 54x + 6

Step-by-step explanation:

Rewrite expressions, so that, we can compare them.

Distributing 18(3x – 1) gives

18(3x – 1) = 18*3x - 18*1 = 54x - 18

In 18(3x + 1) and 3(18x+2) we can perform similarly

18*(3x + 1) = 18*3x + 18*1 = 54x + 18

3*(18x+2) = 3*18x + 3*2 = 54x + 6

Multiplying each term inside parenthesis in (6*9x) + (6*1) gives

(6*9x) + (6*1) = 54x + 6

In (9*6x) – (9*2) and (6*9x) + (6*3) we can perform similarly

(9*6x) – (9*2) = 54x - 18  

(6*9x) + (6*3) = 54x + 18

you should at least use a calculater

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this