Ahandyman knows from experience that his 29 foot ladder rests in its most stable position when the distance of its base from a wall is 1 foot farther than the height it reaches up the wall draw a diagram to represent this situation

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204