Evaluate y = ln (x − 2) for the following values of x. round to the nearest thousandth. x = 3, y = x = 4, y ≈ x = 6, y ≈

The Neperian Logarithms have the number "e" as the base and are symbolized with the abbreviation "ln".

 To evaluate y=ln(x − 2) for the values of x (x=3, x=4 and x=6), you must substitute those values in the function, as below:
 1. x=3
 y=ln(x−2)
 y=ln (3-2)
 y=ln(1)
 y=0

 2. x=4
 y=ln(x−2)
 y=ln(4−2)
 y=ln(2)
 y≈0.693

 3. x=6
 y=ln(x− 2)
 y=ln(6−2)
 y=ln(4)
 y≈1.386
 

The operation is suck a c@ck? !