Ahot-air balloon begins rising from the ground at 4 meters per second at the same time a parachutist's chute opens at a height of 200 meters. the parachutist descends at 6 meters per second. write a system of equations that represents the situation and solve it.

Since the rate of the rising hot air balloon is 4 meters per second, it will be at a certain distance  after t seconds. On the other hand, a descending parachutist travels a distance of where t is also in seconds. They will both be at a certain disrance y when they have traveled a common time t. Writing this in systems of equation we'll get:



Then we can solve the system by equating both equations.





ANSWER: The hot air balloon and the parachutist will be at the same height after 20 seconds.

Sorry i meant b in the other question