One month chris rented 2 movies and 12 video game for a total of $44. the next month he rented 5 movies and 3 video games for a total of $29. find the rental cost for each movie and each video game

M= movie cost
v= video cost

Create two equations with the given information. Solve for one variable in equation one. Use that answer to substitute into equation two.

2m+12v=$44
5m+3v=$29

Solve for one variable in equation 1:
2m+12v=44
Subtract 12v from both sides
2m=44-12v
Divide both sides by 2
m=(44-12v)/2

Substitute m answer in equation two:
5m+3v=$29
5((44-12v)/2)+3v=29
(220-60v)/2+3v=29
Multiply everything by 2 to eliminate the fraction
(2)(220-60v)/2+(2)(3v)=(2)(29)
220-60v+6v=58
220-54v=58
Subtract both sides by 220
-54v= -162
Divide both sides by -54
v= $3.00 cost per video

Substitute v value to find m value:
2m+12v=$44
2m+12(3.00)=44
2m+36=44
Subtract both sides by 36
2m=8
Divide both sides by 2
m=$4.00 cost per movie

Check:
5m+3v=$29
5(4.00)+3(3.00)=29
20.00+9.00=29
29=29

Hope this helps! Please mark me as brainliest if it does. :)

The answer would be -3.9> -4.5