What is the reflection image of p(0, 0) after two reflections, first across x = -3 and then across y = 4?

Hello!

our point is P(0,0) at the beginning, and then we do a reflection across x= -3.

this reflection only affect the x, the initial distance between x and -3 is of 3 units, then when we do the reflection we took this distance and translate it to the other side of the axis -3.

then we go from x = 0, to x= -6, where the distance between - 6 and -3 still is for 3 units, but now for the other side.

When we do the reflection over the axis at y = 4, we think in the same way, the x part remains unchanged, it only affects the y part.

then the distance between y and 4 is for 4 units, then y translates by 4 units to the "other side" of 4, this is 4 + 4 = 8, after the reflection y is equal to 8.

so the point (0,0) is now (-6,8)

is kinda hard to explain this without a drawing, if you have any problem understanding it, please write to me.

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

the correct answer is 5 6 and 7