What is the equation of a line with a slope of 3 and a point  (3,  1) on the line? express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.

The equation of a line can be written as:

Where (xo, yo)=(3, 1)


The equation of the line is:

We are already given the slope (3) so we can set that for m. 

y = 3x + b

Now all we need is the y-intercept. Using the slope and the ordered pair (3,1), we can calculate at what number the line will cross directly on the y-axis. For the line to cross directly on top of the y axis, the x-value must be 0. When the x equals 0, whatever the y equals is our y-intercept.

Currently the x value is 3. We need to find a way to turn the 0. Use the slope formula ( = 3;   Note: that x equals  ) and reverse it to . Note that the rise deals with the y-value whilst the run deals with the x-value. If it's positive that means +. If it's negative that means -. We turned the slope negative so we could do inverse operations. This let's us find out what the y-value would equal if x was 0. 

(3,1) -> (3 - 1, 1 - 3) -> (2, -2) -> (2 - 1, -2 - 3) -> (1,-5) -> (1 - 1, -5 - 3) -> (0,-8).

When x was 0, y was -8. Therefore the y-intercept is -8.

Equation: y = 3x - 8.

View the attachment to see it graphed.

A. p = 2(l + w)p/2 - l = ww = p/2 - l b. while isolating the variable w in the equation, i first divided both sides by 2 and then i subtracted l from both sides. i hope this .