If there are 12 teams in a basketball tournament and each team must play every other team in the eliminations, how many elimination games will be?

In each game, the first team can be any one of the  12 ,
and the second team can be any one of the remaining  11 .

Total number of ways to match them up = (12 x 11) = 132 .

BUT ... Every game can be described as two different match-ups ...
either as ' A ' playing ' B' , or as ' B ' playing ' A '.

Although there are 132 ways to make a match-up, every possible
pair of teams shows up twice in that list. 

So in order for every team to play every other team, there are
only  (132 / 2) = 66 different games required.

I’m confused as to what you are asking 66 2/3 percentage wise