Afunction is represented by y = cos (2π/5)x - 1. determine the amplitude and period of the function. what is the equation of the midline? a) amplitude is 1; period is 5; y = 0 b) amplitude is 1; period is 2/5; y = 1 c) amplitude is 1; period is 5; y = −1 d) amplitude is 1; period is 2π; y = −1 ( explain how you get it)

Given that: y = cos(2pi/5)x -1

The general form of cos function is y = A cos(Bx+C) +D

So amplitude = A=1

Period = 2pi/B=2pi/(2pi/5)= 5

Phase shift = -C/B= 0

Vertical shift = D=-1

So the equation of the midline is y=-1

Sot he correct option is C.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.