Worth 20 points try to answer as many as possible tell me which one you are answering and tell me how you got the answer and your work 1) y varies inversely with x. if y= 40 when x= 16, find x when y= -5. 2) y varies directly with x. if y= 15 when x= -18, find y when x=1.6. 3) if x and y vary directly, as x decreases, what happens to the value of x? 4) if x and y vary directly, as y increases, what happens to the value of x?

1) x = (40/-5)*16 = -128
.. Since the variation is inverse, (old y)/(new y) = (new x)/(old x). Note the new/old ratios are upside down. Thus (new x) = (old x)*(old y)/(new y), as above.

2) y = (1.6/18)*-15 = -1 1/3
.. Since the variation is direct, (new y)/(old y) = (new x)/(old x)

3) x DECREASES
.. When variation is direct, both variables move in the same direction. Here, the problem statement tells you what happens to x! (Perhaps a typo?)

4) x INCREASES
.. See 3).

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60

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