You are the only bank teller on duty and you want to take a break for 10 minutes but you don't want to miss any customers. suppose the arrival of customers can be models by a poisson distribution with mean of 2 customers per hour. what's the probability that 2 or more people arrive in the next 10 minutes?

The probability that 2 or more people arrive in the next 10 minutes is;

P(X ≥ 2) =  0.0447

This is a poisson distribution problem with the formula;

P(X = x) = [e^(-μ) × μˣ]/x!

Where;

x is number of successes

μ is the mean in the time interval given

Since we have a mean of 2 customers per hour and want to find the probability that 2 or more people arrive in the next 10 minutes. Thus;

μ = (2 × 10)/60

μ = 0.333

Thus,  probability that 2 or more people arrive in the next 10 minutes is;

P(X ≥ 2) = 1 - (P(X = 0) + P(X = 1))

P(X = 0) =  [e^(-0.333) × 0.333⁰]/0!

P(X = 0) = 0.7165

P(X = 2) =  [e^(-0.333) × 0.333²]/2!

P(X = 2) = 0.2388

Thus;

P(X ≥ 2) = 1 - (0.7165 + 0.2388)

P(X ≥ 2) =  0.0447

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4.47% probability that 2 or more people arrive in the next 10 minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which

x is the number of sucesses

e = 2.71828 is the Euler number

is the mean in the given time interval.

Mean of 2 customers per hour.

What's the probability that 2 or more people arrive in the next 10 minutes?

10 minutes, so

Either less than two people arrive, or more than two do. The sum of the probabilities of these events is decimal 1. So

We want . So

In which

4.47% probability that 2 or more people arrive in the next 10 minutes

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.