Afactory makes tv's and video machines. checking for faults regularly, on average, 5 out of every 300 tv's are faulty and 8 out of every 200 video machines are faulty.
a) if i check two tv's and 1 video machine at random, what's the probability that exactly one of them is faulty?
b) how many tv's must be checked so that the probability of at least one being faulty is greater than 0.95.

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hope this ^_^

do you see a nakes

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!