Find the x-intercept for the line represented by this equation.
3y=2x+6
a. (0, –3)
b. (–3, 0)
c. (0, 2)
d. (2, 0)

find the y-intercept for the line represented by this equation.
-2y=4x+8
a. (–4, 0)
b. (0, –4)
c. (0, –2)
d. (–2, 0)

answer: the answer is fre sha voca do

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)