When fritz drives to work his trip takes 48 minutes, but when he takes the train it takes 40 minutes. find the distance fritz travels to work if the train travels an average of 6 miles per hour faster than his driving. assume that the train travels the same distance as the car?

Let x be the speed when Fritz is driving
x + 6 will be the train speed
Converting minutes to hrs
48 mins = 48/60 = 4/5 hrs
40 mins = 40/60 = 2/3 hrs

Remember formula distance = rate * time
distance driving = (4/5)x
distance train traveling = (2/3)(x+6)

The train travels the same distance as the car
4/5x = 2/3(x+6)
4/5x = 2/3x + 4
4/5x - 2/3x = 4
basic elementary school math
2/15x = 4
2x = 40
x = 30 miles/hrs is the speed he driving.
distance train traveling = 2/3(30 + 6) = 24 miles 
check with the distance he driving
4/5(30) = 24 miles

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