How do i do
(5y-4)^2
with steps?
you!

first, you have to turn (5y-4)^2 into (5y-4)(5y-4).
From there, you would FOIL, or multilpy the 5y by the 5y, which is 25y^2, the multiply the 5y by the -4, which is -20y, then multiply the -4 by the 5y which is -20y, and then multiply the -4 by the -4, which is 16. It would then look like this: 25y^2 - 20y - 20y +16. Then you would add (or in this case, subtract) like terms. You would add -20y and -20y, which is -40y. The end expression would be 25y^2 - 20y +16. Hope this helps!

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