Prove that (160x^5)/(8x^2 (4x+5x+x^2))+14y-(7y+y^3 )-3y+20z/(13z-(3z+5z) )+15q-(4q*2q)+3q^2+[3jn+n(n^2 )]2+(160j^2)/(5j*8j) is equal to (20x^2)/9+20x+4y-y^3+15q-5q^2+6jn+2 n^3+8

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

answerim :

n

step-by-step explanation:

im not sure but my dad knows

- (2, -7)

- lines r and s and lines t and u must be parallel