The sum of 6 consecutive integers is 393 what is the third number in the sequence

x+1, x+2, x+3, x+4 and x+5.

The sum of these six integers is 393 so we can write:

x+x+1+x+2+x+3+x+4+x+5=393

6x+1+2+3+4+5=393

6x+15=393

6x+15−15=393−15

6x+0=378

6x6=3786

x=63

Because the first integer is 63 then the third would be x+2 or 63+2=65

Hope its helps :)

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72