The longest side of an acute isosceles triangle is 8 centimeters. rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides? a: 4.0 b: 4.1 c: 5.6 d: 5.7

4.1cm
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It is an acute isosceles triangle, so the vertex angle is smaller than 90.
if the vertex angle is 90, then it is a 45-45-90 triangle, when the longest side (the hypotenuse) is 8, each leg is 8/√2=5.65685

Because the vertex angle needs to be smaller than 90, the two equal side is larger than 5.6568, I'd go with D.

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