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solve for w.

a.) w= 4k-2b / -5

b.) w= 3k^2- b / -5

c.) w= -3k^2 - b / 5

d.) w= 3k^2 + 2b / -5

K = (2b-5w)/3k

Cross multiply

K × 3k = 2b - 5w

5w = 2b-3k²

w = (2b-3k²)/5...

In these questions, when there's no actual numbers, they want you to express w in terms of other unknowns. Therefore, the procedure is to Isolate w.

k = (2b - 5w) / 3k

Do it normally like how you would do in algebra equations, Shift all the other numbers and unknowns which are on the side of w away until only w is left there.
So with this equation, first thing we would like to shift /3k away, so Shift this whole thing to the other side and turn it into x3k.

k x 3k = 2b - 5w

k x k equals to k^2,
So we can write this
3k^2 = 2b - 5w

Now Shift 2b to the other side too, and Change it into - 2b.

3k^2 - 2b = -5w

Last step, Shift x-5 to the other side, turning it into /-5.

(3k^2 - 2b) / -5 = w

Swap places and you'll get w = (3k^2 - 2b) / -5, so the answer is A.