Determine if the columns of the matrix form a linearly independent set. justify your answer. left bracket start 4 by 3 matrix 1st row 1st column negative 2 2nd column negative 1 3rd column 0 2nd row 1st column 0 2nd column negative 1 3rd column 3 3rd row 1st column 1 2nd column 1 3rd column negative 6 4st row 1st column 2 2nd column 1 3rd column negative 12 endmatrix right bracket −2 −1 0 0 −1 3 1 1 −6 2 1 −12

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.