The sum of 3 consecutive odd integers is 87.find the equation used to solve this problem and the three integers.

The first odd integer is x. The next odd integer will be x+2. and the next is x+4. Then we can say that (x)+(x+2)+(x+4)=87 
working that out yields 3x+6=87 
and thus 3x=81
and by consequence x=27

and thus our 3 odd integers are 27,29 and 31

Aand b are correctly balanced reactions. they have the same number of atoms in both sides of the reaction