Arectangular room is 6 6 meters longer than it is wide, and its perimeter is 28 28 meters. find the dimension of the room

We know that perimeter is equal to 2l+2w or l+l+w+w. 
We also know that the length is 6 meters longer than the width. 

Based on this we can create the following formula to find the dimensions: 

28= (w+6)+(w+6)+w+w

Then to solve, it's just simple algebra. 

First, combine like terms: 28= w+w+w+w+6+6     28= 4w+12

The next thing we do is isolate the variable by subtracting 12 from each side: 28-12 = 4w+12-12        16= 4w

The next thing we do is divide both sides by the coefficient (4): 16/4 = 4w/4

And this gives us the answer that w=4. 

Now to find the dimensions: 
We know that the width is equal to 4. 
We also know that the length is equal to 6 more than the width. If the width is 4 then the length is 4+6 or 10. 

So there you have it, the dimensions of the room would be 4x10. 

This does not make sense