1. find the equation of the circle with center at (-3,1) and through the point (2,13) 2. what is the equation of the circle with the center at (2,4) and the radius of 6. (show all work and you)

Try this solution:
Common view of the equation of the circle is (x-a)²+(y-b)²=r², where point (a;b) is centre of the circle, r - radius.
1. using the coordinates of the centre and point (2;13) it is possible to define the radius of the circle: r=√(5²+12²)=13;
the equation is (x+3)²+(y-1)²=13² or (x+3)²+(y-1)²=169;
2. using the coordinates of the centre and the radius: (x-2)²+(y-4)²=6² or (x-2)²+(y-4)²=36.

We’re gonna need a picture to refer to in order to figure it out. try reposting your question with the picture included.