Aculture started with 6000 bacteria after 3 hours ot grew to 7200 bacteria predict how many bacteria will be present after 19 hours

19038

Step-by-step explanation:

Given : A culture started with 6000 bacteria after 3 hours to grew to 7200 bacteria

To Find: Predict how many bacteria will be present after 19 hours

Solution:

General Form of exponential function:

where y is the amount after x hours

x is the time

a is the initial amount

b is the growth factor

Bacteria initial amount= a = 6000

Time = x = 3 hours

Amount of bacteria after 3 hours = 7200

Substitute the values in the general form

Now we are supposed to find how many bacteria will be present after 19 hours

So, Bacteria initial amount= a = 6000

Time = x = 19 hours

Amount of bacteria after 19 hours = y

Substitute the values in the formula:

Hence there will be approximately 19038 bacteria present after 19 hours

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form