Joel ca drive his car 450 miles at a steady speed using 15 gallons of gasoline. make a rate table showing the number of miles his car can be driven at this speed. show 1 2 3 4 5 6 7 8 9 10 gallons of gas

Since his speed is maintained, we can remove it from consideration. We need to know the equivalent of 1 gallon to the number of miles he has to travel.

450mile ÷ 15 gallons = 30 miles per gallon

We can use this formula to know the total number of miles traveled based on the number of gallons of gasoline placed.

y = 30(x)   y = total number of miles traveled, x = gallons of gasoline used

y = 30(1)   = 30 mi
y = 30(2)   = 60 mi
y = 30(3)   = 90 mi
y = 30(4)   = 120 mi
y = 30(5)   = 150 mi
y = 30(6)   = 180 mi
y = 30(7)   = 210 mi
y = 30(8)   = 240 mi
y = 30(9)   = 270 mi
y = 30(10) = 300 mi

A’b’c’ are the coordinates to the new location of the transformed triangle abc. find the distance between the coordinates points to use for your calculations.