Ellen wishes to mix candy worth $1.45 per pound with candy worth $3.74 per pound to form 27 pounds of a mixture worth $3.06 per pound. how many pounds of the more expensive candy should she use? r.

Let x pounds of candy worth $1.45 per pound are used.

So price of x pounds = 1.45x.............(1)

Total mixture is of 27 pounds , so for other candy it will be (27-x) pounds

Let (27-x) pounds of candy worth $3.74 per pound are used.

So price of (27-x) pounds = 3.74(27-x)............(2)

Quantity of total mixture =27 pounds

price of one pound of mixture = $3.06

Price of 27 pounds of mixture = 3.06 *27 = $82.62........(3)

Price of mixture = Price of first type + price of second type

Using (1) (2) and (3)

Now let us calculate x from here,

x=8.02

Now the expensive candy quantity is (27-x) pounds

So quantity of expensive candy = (27-8.02) = 18.98 pounds.

step-by-step explanation:

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about the problem:

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