The sum of twelve and a number is no greater than sum of twice the number and -8

1. Write as an algebraic equation:

12 + n ≤ 2n - 8

2. Solve for n.

12 + n - 12 ≤ 2n - 8 - 12

n ≤ 2n - 20

n - 2n ≤ 2n - 20 - 2n

-n ≤ -20

Multiply both sides by -1 (this means you must flip the inequality sign).

n ≥ 20

FINAL ANSWER: n ≥ 20

Hope this helps! Feel free to ask for clarification.

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