Leon made 4 liters of lemonade for the party, but it was too strong, it was 14% lemon juice. how much 8% lemonade should he add to make a mixture that is 10% lemon juice? can someone show me how to solve this using the table or bucket method?

Item       Number of Liters          Percentage of LemoneA                    4        14%B                    x         8%Result           4+x            10%
For a mixture of solutions to form a resulting solution, we know
V1 * N1 + v2 * N2 = V * N
where, V1 = Volume of mixture of 1 N1 = Concentration of mixture 1V2 = Volume of mixture of 2 N2 = Concentration of mixture 2
V = volume of mixture N = Concentration of mixture
So solving we get:
(4+x)*10 = 4*14 + x * 8or, 10x-8x = 4*14-4*10or, 2x = 16or x = 8
so 8 litres of the solution B must be added to the solution

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