Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is also 53. 6f – 1 evaluated at f = 3 is 17. what is 2f + 4f + 2 – 3 evaluated at f = 3?

We have that

the expression 2f + 4f + 2 – 3> we can group it   (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

let's check it
[2*3 + 4*3 + 2 – 3]> [6+12+2-3]=[20-3]=17> is ok

The answer for this is 9/1253decimal form 0.007

Letter b sorry i’m i’m wrong xx