Find two consecutive odd intefers whose product is 63

Hello,

Let's assume 2n-1 the first integer
and 2n+1 the second.

(2n-1)*(2n+1)=64
(2n)²-1=64
4n²=64
n²=16
==>n=4 or n=-4
If n=-4 then 2n-1=2*(-4)-1=-9 and 2n+1=2*(-4)+1=-7
If n=4 then 2n-1=2*(4)-1=7 and 2n+1=2*(4)+1=9

(-9,-7) and (7,9) are the 2 solutions.