What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5? y = x – 8 y = x + 1 y = x + 1 y = x + 10

Step-by-step explanation:

Given equation of line :

Standard form of equation of line =  ---A

Where m is the slope

Convert the given equation in standard form

So, slope =

If the two lines are perpendicular then the product of their slopes is -1

Let n be the slope of required equation of line

So,

Substitute this value in A

 --B

Now we are given that the required perpendicular line passes through the point (–6, 1)

So, substitute  (–6, 1)  in B

Substitute the value of c in B

Hence the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5? is  

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.