The standard form of the equation of a circle is (x−5)2+(y−6)2=1. what is the general form of the equation? x2+y2−10x−12y+60=0 x2+y2−10x−12y−62=0 x2+y2+10x+12y+62=0 x2+y2+10x+12y+60=0

x2+y2−10x−12y+60=0

Step-by-step explanation: Just confirming the answer :)

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!