Find all the zeros of the equation. -3x^4+27x^2+1200=0 i don't really understand this. show me the steps! !

You can either use the Pythagorean theorem right away (a = -3, b = 27, c = 1200) or Try factoring the polynomial to find the zeros.

I would factor and start by dividing everything by -3.

-3x^4 + 27x^2 + 1200 = 0
-3(x^4 - 9x^2 - 400) = 0

If you divide by -3 on both sides you see that the -3 is now gone. 0/-3 = 0

x^4 - 9x^2 - 400 = 0
factor further or use Pythagorean theorem.

(x² - 25)(x² + 16) = 0

Solve for the x-values by setting each one equal to zero.

x² - 25 = 0
x² = 25
x is +5 or -5

x² + 16 = 0
x² = -16
x = √(-16)
Two non-real solutions
x is +4i or -4i

The answer is 4 points

so the perpendicular line goes through the given pointyou would get a perpendicular line at some random location

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.