How many real number solutions does the equation have? 0=5x^2+2x-12 a- one solution b- two solution c-infinity many solutions d-no solutions

5x^2+2x-12=0 is a quadratic equation. For any ax^2 + bx + c = 0, the solution can be found by completing the square to find the equations 
 x=(-b+sqrt(b^2-4ac))/2a and x=(-b-sqrt(b^2-4ac))/2a  
 Substituting using the equation 0=5x^2+2x-12
 x=(-2+sqrt(2^2-4(5)(-12)))/(2(5)) and x=(-2+sqrt(2^2-4(5)(-12)))/(2(5)) 
 Since the sqrt(244) is a real number, there are two real solutions.