Three consecutive even integers add to −6. what are these integers?

Let's consider the smallest even integer = x.

then second even integer = (x + 2).

and third even integer = (x + 4).

So three consecutive even integers would be x, (x + 2), and (x + 4).

The sum of these numbers is -6. Its equation would be as follows :-

x + (x + 2) + (x + 4) = -6

3x + 6 = -6

3x = -6 - 6

3x = -12

x = -4

So first number = x = -4

second number = (x + 2) = -2

third number = (x + 4) = 0

Hence, three consecutive even integers are -4, -2, and 0

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

triangle and cube

step-by-step explanation: