Did i find the area of the composite figures correctly in the pic? if not, pls?

No, in problem 1
you said that area of triangle=bh when it should be 1/2bh
the area should be 9 not 18 so triange=9
aera of rectangle is correct
so
27+9=36 in^2 is answer

2. it is 1 rectangle 1 triangle 1 square  you forgot the square
rectangle=12 times 4=48
square=4 times 4=16
triangle=1/2bh=1/2(8)4=16
add

48+16+16=80 in^2

remember that
triangle=1/2(base times height)
draw immaginary lines and split shapes, it could help to seperate shapes or/and mmove them around and regroup them