Mathematics, 29.07.2019 16:00 lilbit404

Suppose you are given the graph of y = f (x) . explain how to obtain the graphs of a. y = f (x / 2) b. y = f (x - 2) c. y = f (2 x - 1)

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Suggest you make yourself a list of transformations and their associated rules. The ones you're concerned with here are
.. f(x) ⇒ f(kx) . . . . . . horizontal compression by a factor of k
.. f(x) ⇒ f(x -k) . . . . . right shift by k units

a) Each point (x, y) gets moved to (2x, y). The graph is expanded horizontally by a factor of 2.

b) Each point (x, y) gets moved to (x+2, y). The graph is translated horizontally 2 units to the right.

c) Each point (x, y) gets moved to ((x +1)/2, y). The graph is translated horizontally 1 unit to the right, then compressed horizontally by a factor of 2.

Answer from: Quest

starting with:

5 + x - 12 = 2x - 7

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)

5 - 12 = x - 7 (combine and cancel x's from both sides)

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)

0 = x (add numbers together on both sides)

so in order for the equation to be true, x must be 0.

trying x = -0.5

5 + x - 12 = 2x - 7 (original equation)

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)

5 + -0.5 - 12 = -1 - 7 (did multiplication)

-7.5 = -8 (did addition on both sides)

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.

trying x = 0

5 + x - 12 = 2x - 7 (original equation)

5 + 0 - 12 = 2(0) - 7 (plug in value of x)

5 + 0 - 12 = 0 - 7 (did multiplication)

-7 = -7 (did addition on both sides)

since -7 equals -7, that demonstrates that the value of 0 for x is correct.

trying x = 1

5 + x - 12 = 2x - 7 (original equation)

5 + 1 - 12 = 2(1) - 7 (plug in value of x)

5 + 1 - 12 = 2 - 7 (did multiplication)

-6 = -5 (did addition on both sides)

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

Answer from: Quest

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60

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